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14h^2+9h-8=0
a = 14; b = 9; c = -8;
Δ = b2-4ac
Δ = 92-4·14·(-8)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-23}{2*14}=\frac{-32}{28} =-1+1/7 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+23}{2*14}=\frac{14}{28} =1/2 $
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